;; reverse order of element in A[0..9]
;;   simplest way is to use another array B[0..9]
;;   i = 0, j = 9,  
;;   B[j] = A[i], i++, j-- 
;;   and copy B back to A

;;   i = 0, j = 9
;;   while i <= 9     put to B in reverse order
;;      B[j] = A[i]
;;      i = i + 1
;;      j = j - 1
;;   i = 0
;;   while i <= 9     copy back to A
;;      A[i] = B[i]
;;      i = i + 1

;; let r1 = i, r2 = j, r3 = test, r4 = A[i]

.symbol 
	A 50
	B 80
.code 0
	mv r1 #0
	mv r2 #9
:loop1	le r3 r1 #9
	jf r3 copy
	ld r4 @A r1
	st @B r2 r4
	add r1 r1 #1
	sub r2 r2 #1
	jmp loop1
:copy 	mv r1 #0
:loop2	le r3 r1 #9
	jf r3 exit
	ld r4 @B r1
	st @A r1 r4
	add r1 r1 #1
	jmp loop2
:exit	trap 0
.data 50
	11 22 33 44 55 66 77 88 99 100
.end